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PSYCHO15rus [73]

3 years ago

7

What is the solution to the equation

2 answers:

nignag [31]3 years ago

8 0

26.....................................................................................................................................................................................................................

kodGreya [7K]3 years ago

4 0

Answer:

You have to combine like terms and use PEMDAS.

Step-by-step explanation:

If you haven´t learned about PEMDAS it stand for Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction; the correct and simplest way to do long multi step equations. So you would actually substitute x for each one of the things it shows x equals, solve the equation and put it down, if that´s what they are looking for. Solve for the X

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Okay so clearly I'm not so smart but I need help again..?

Alla [95]

Lateral surface area, is the area that is not including bases
so it is an area of free rectangles
3*(5*8)=3*40=120 cm²

5 0

3 years ago

Which expression is equivalent to the one in the picture?

Ne4ueva [31]

Answer:

d.

Step-by-step explanation:

To convert a root to a fraction in the exponent, remember this rule:

$\sqrt[n]{a^{m}}=a^{\frac{m}{n}}$

The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.

In this question, the index is 4.

The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.

$\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}$

To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, $\sqrt[4]{16}$ = 2.

For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.

$2x^{\frac{15}{4}}y^{\frac{17}{4}}$

5 0

3 years ago

A line passes through the point (4, -6) and has a slope of 3/2 . Write an equation in slope-intercept form for this line.

tatyana61 [14]

A slope intercept form: y = mx + b where m = slope and b = y -intercept

A slope of 3/2 is given

So y = 3/2 x + b

To find b:

b = y - mx

A line passes through the point (4, -6)

b = -6 - (3/2)(4)

b = -6 - 6

b = - 12

Answer

Equation in slope intercept form: y = 3/2 x - 12

8 0

3 years ago

Read 2 more answers

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago

I swear when I actually need help nobody ever answers

Llana [10]

Answer:

stop asking questions and u wont have to worry abt that

Step-by-step explanation:

if u stop asking maybe u wont get an answer

8 0

3 years ago