Question

It is estimated that t months from now, the population of a certain town will be changing at the rate of 4+ 5t^2/3 people per month. If the current population is 10,000, what will the population be 8 months from now?

Answer 1

Answer:

240000

Step-by-step explanation:

Represent the exponential equation.

$10000 (5 {t}^{ \frac{2}{3} } + 4) =$

Replace 8 with t

$10000(5(8) {}^{ \frac{2}{3} } + 4)$

$10000(5 \times 4 + 4)$

$10000(24) = 240000$

Answer 2

Answer:

I think it would be 10,128

Step-by-step explanation:

$=\int _0^84dt+\int _0^85t^{\frac{2}{3}}dt$

= 32 + 96

= 128 + 10,000