How to write the decimal for 762-222-2945

(radical) √75 estimated to the nearest hundredth thank u :3

frosja888 [35]

The answer is 2.646 hope it helps

6 0

3 years ago

A dragonfly can fly up to 36 miles per hour

Marysya12 [62]

True, A dragonfly can fly up to 36 miles per hour.

Answer: True

5 0

3 years ago

The segments shown below could form a triangle. 4,3,6 PLZ HELP ASAP

Rzqust [24]

Answer:

Option A. True

Step-by-step explanation:

we know that

The Triangle Inequality Theorem, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

we have

4,3 and 6

Applying the triangle inequality theorem

case 1) 4+3 > 6 -----> is true

case 2) 3+6 > 4 ----> is true

therefore

The given segments could form a triangle

Is true

6 0

3 years ago

Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.

lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is tested if the mean lifetime is not greater than 220,000 miles, that is:

$H_0: \mu \leq 220000$

At the alternative hypothesis, it is tested if the mean lifetime is greater than 220,000 miles, that is:

$H_1: \mu > 220000$ .

We have the standard deviation for the sample, thus, the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem:

$\overline{x} = 226450, \mu = 220000, s = 11500, n = 23$

Then, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}$

$t = 2.69$

We have a right-tailed test(test if the mean is greater than a value), with t = 2.69 and 23 - 1 = 22 df.

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0

2 years ago

WILL MARK BRAINLIEST PLEASE HELP thanksss

Alenkasestr [34]

The image of rectangle JKLM after a reflection over the y-axis around the origin is J = (6, -2), K = (6, -1), L = (0, -1) and M = (0, -2)

<h3>How to graph the image of rectangle JKLM after a reflection over the y-axis around the origin?</h3>

From the graph, the coordinates of the rectangle are:

J = (-6, -2)

K = (-6, -1)

L = (0, -1)

M = (0, -2)

The rule of a reflection over the y-axis around the origin is

(x, y) = (-x, y)

When the above rule is applied, we have the image to be:

J = (6, -2)

K = (6, -1)

L = (0, -1)

M = (0, -2)

Hence, the image of rectangle JKLM after a reflection over the y-axis around the origin is J = (6, -2), K = (6, -1), L = (0, -1) and M = (0, -2)