Given =
n=6,
r=1/4
a=2
Sn = a+ar+ar²+ar³+ar⁴+ar⁵= 2+0.5+0.125+0.03125+0.0078125+0.00195~ 2.67
Answer: 1326 students won't come to school
Step-by-step explanation:
All you have to do is find out 85% of 1560 which is 1326 students!
Answer:
Samantha payed 12.71$ for her purchase.
Step-by-step explanation:
I may have misunderstood the question, but it looks like you can use a calculator for this!
6.19 + 2.85 + 2.29 + 1.38 =
12.71
Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
This would be the identity property of addition telling us that any number added to zero is that number (i.e. 6 added to zero is still 6)