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san4es73 [151]
1 year ago
6

Determine the equation of the circle graphed below. (pt 3 of help fast)

Mathematics
1 answer:
dmitriy555 [2]1 year ago
8 0
<h2>Circular Equations</h2>

Circular equations are typically organized in the following format:

(x-h)^2+(y-k)^2=r^2

  • (h,k) is the center of the circle
  • <em>r</em> is the radius

<h2>Solving the Question</h2>

We're given:

  • The center of the circle: (-4,-7)
  • The radius: 2 units

Plug these given values into the formula:

(x-h)^2+(y-k)^2=r^2\\(x-(-4))^2+(y-(-7))^2=2^2\\(x+4)^2+(y+7)^2=2^2\\(x+4)^2+(y+7)^2=4

<h2>Answer</h2>

(x+4)^2+(y+7)^2=4

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A soccer field has a perimeter of 326 metres. Its area is 6370 square metres. What are the dimensions of the field?
Burka [1]

Answer:

Step-by-step explanation:

chiều dài:x,x>0

chiều   rộ:y

\left \{ {({x+y)*2=326} \atop {xy=6370}} \right.

\left \{ {{x+y=163} \atop {xy=6370}} \right.

\left \{ {{y=163-x} \atop {xy=6370}} \right.

\left \{ {{y=163-x} \atop {x*(163-x)=6370}} \right.

\left \{ {{y=163-x} \atop {163x-x^{2} =6370}} \right. \\

\left \{ {{y=163-x} \atop {x_{1} =98; x_{2} =65}} \right.

\left \{ {{y=65} \atop {x=98}} \right.

4 0
2 years ago
A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school
Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.                                                    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15  

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15  

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85  

Calculation the value from standard normal z table, we have,  

P(z < 1.036) = 0.85

\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

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