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Answer with explanation</u>
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Let
be the population mean.
As per given , we have

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given
, so we perform one-tailed z-test.
Test statistic : 
, where
= Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 ,
,
,
, we have

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
12X is the period of what is the period of f : R→R, f(x) = tan(x 3)?
Short answer: 98
Remark
when you have an average of 71, it's like saying that you took 4 quizzes and got 71 on all of them.
Step One
Find the total point count for the 4 quizzes.
T_4 = 71 * 4 = 284
Step Two
Create an equation that will give you the necessary point count to average 86.
284 + 5*x = 86 * 9
Why did we do this? It is because you have 9 quizzes altogether. All nine must be something that gives a point count of 86 on each quiz. You have to put together 9 such quizzes with a total count of 774.
Step three
Solve the equation.
284 + 5x = 774 Subtract 284 from both sides.
5x = 774 - 284
5x = 490 Divide by 5
x = 490/5
x = 98
You must get an average of 98 on the next 5 quizzes
Answer: 98 <<<<<
Answer:
division
Step-by-step explanation:
2x/2=8/2=x=4
x=4