Question

In ΔABC, m∠B = 90°, cos(C) = 15/17 , and AB = 16 units. Based on this information, m∠A = °, m∠C = °, and AC = units. Note that the angle measures are rounded to the nearest degree.

Answer 1

Answer:

m∠A=62°, m∠C=28°, AC=34 units

Step-by-step explanation:

Answer 2

Answer:

 m∠C=28°, m∠A=62°, AC=34.1 units

Step-by-step explanation:

Given In ΔABC, m∠B = 90°, $cos(C)=\frac{15}{17}$, and AB = 16 units. we have to find m∠A, m∠C, and AC.

As, $cos(C)=\frac{15}{17}$

⇒ $\angle C=cos^{-1}(\frac{15}{17})=28.07^{\circ}\sim28^{\circ}$

By angle sum property of triangle,

m∠A+m∠B+m∠C=180°

⇒ m∠A+90°+28°=180°

⇒ m∠A=62°

Now, we have to find the length of AC

$sin 28^{\circ}=\frac{AB}{AC}$

⇒ $AC=\frac{16}{sin 28^{\circ}}=34.1units$

The length of AC is 34.1 units