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vaieri [72.5K]
3 years ago
5

A person runs 1/5 miles in 1/40 Hour The person's speed is miles per hour.

Mathematics
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

1/5 × 40 = 8

the person's speed is 8 miles per hour

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What is 9x-7y=-7 in slope intercept form?
Novay_Z [31]
Slope intercept form is y = mx + b

So if you start with 9x - 7y = -7, the first thing you need to do is move the 9x to the other side of the equation by subtracting it from both sides.
       9x - 7y =      -7
       -9x          -9x

Now you have -7y = -9x -7

For the equation to be in slope intercept form now you should divide every term by the number in front of your y.  In this case divide every term by -7
    -<u>7y</u> =  <u>-9x</u>  <u>-7</u>
      -7      -7   -7

That leaves you with: y = 9x/7 + 1


4 0
3 years ago
8+(14+6) FIND EASIER EXPLAIN WHY
alexandr1967 [171]

Hi there and welcome to Brainly!


The answer to 8+(14+6) = 28. The reason for this is you add what is in parenthesis first then you add the number outside of the parenthesis. This follows the PEMDAS rule which is called the order of operations. PEMDAS is an acronym which stands for Parenthesis, Exponents, Multiplication/Division, and Addition/Subtraction, this is the order you should follow when solving any problem.


If you have anymore questions please feel free to ask them.

Your friend, ASIAX

8 0
3 years ago
A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

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