Ask question

Ask question

All categories

3 years ago

5

A person runs 1/5 miles in 1/40 Hour The person's speed is miles per hour.

1 answer:

Minchanka [31]3 years ago

5 0

Answer:

1/5 × 40 = 8

the person's speed is 8 miles per hour

You might be interested in

I need help with this mean, median, and averages etc. Brainliest is depending on correct answers and explanations. And don't loo

V125BC [204]

Answer:

Red is spelled as LSTER

Step-by-step explanation:

I think its a... I think its a carrot

4 0

3 years ago

If the radius of the Cicular ground is 6m<br>find, the area of ground #plz help

Fed [463]

Answer:

113.142857 m²

Step-by-step explanation:

As per the provide information in the given question, we have :

Radius of the circular ground = 6 m

We are asked to find the area of the ground.

Since, it is in the shape of circle, so we'll apply here the formula to find the area of the circular ground.

We know that,

>> Area of circle = πr

>> Area of the ground = $\sf \dfrac{22}{7}$ × 6 m × 6 m

>> Area of the ground = $\sf \dfrac{22}{7}$ × 36 m²

>> Area of the ground = $\sf \dfrac{792}{7}$ m²

>> Area of the ground = 113.142857 m²

$\therefore$ <u>Therefore</u><u>,</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ground</u><u> </u><u>is</u><u> </u><u>113.142857 m²</u><u>.</u><u> </u>

3 0

3 years ago

9w-4w+6<1+5w supposed to combine like terms

Mariana [72]

Answer/Step-by-step explanation:

Given:

$9w - 4w + 6$ < $1 + 5w$

To solve, collect like terms.

Subtract 5w from both sides

$9w - 4w + 6 - 5w$ < $1 + 5w - 5w$

$9w - 4w - 5w + 6$ < $1$

$6$ < $1$ (incorrect)

The inequality given has no solution or an information is missing.

6 0

3 years ago

The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti

DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

$P(t)=10000(0.2)^t$

1) $P(0)$ is the population initially.

$P(1)$ is the population after a year.

$\frac{P(1)}{P(0)}$ represents the population increase factor.

So let's evaluate that fraction:

$\frac{P(1)}{P(0)}$

$\frac{10000(0.2)^1}{10000(0.2)^0}$

$\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2$

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

$P(t)=10000(0.2)^{t}$

We want t to represent months.

A full year is 12 months, in a full year we have that $P(1)=10000(0.2)^1=10000(0.2)=2000$

So we want a new P such that $P(12)=2000$ since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) $P(12)=10000(0.87449)^{12}=2000 \text{approximately}$

b) $P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}$

c) $P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}$

d) $P(12)=10000(0.87449)^{12+12}=400 \text{approximately}$

So a is the function we want.

Also another way to look at this:

$P(t)=10000(.2)^t$ where $t$ is in years.

$P(t)=10000(.2^\frac{1}{12})^t$ where $t$ is in months.

And $.2^\frac{1}{12}=0.874485 \text{approximately}$

8 0

3 years ago

Is this right? If not plz let me know!!! HURRY PLZ!!!!

labwork [276]

Answer:

Math isnt my strongest subjuect but i believe it it right.

4 0

3 years ago