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nataly862011 [7]
3 years ago
14

Jose wanted to make a graph to show his budget for the month. What type of graph would be the most appropriate to graph for Jose

to use?
A. Bar Graph
B. Line Graph
C. Histogram
D. Circle Graphs
Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

D)

Step-by-step explanation:

You might be interested in
How to use a protractor.
damaskus [11]

Answer:

You can see below!

Step-by-step explanation:

Basically, a protractor is used to measure angles. You probably have a semi-circle shaped one. Looking at the bottom middle of the protractor should show you lines intersecting each other at a point. If you have an angle on a piece of paper, place that point on the ends of the line segments making up the angle. Then, check where each line of the angle crosses the numbers on the outer rim. That shows you the measure of the angle you are examining. It can be a bit tricky, but with practice you'll get it in no time!

8 0
3 years ago
The average student-loan debt is reported to be $25,235. A student believes that the student-loan debt is higher in her area. Sh
yulyashka [42]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 25235

For the alternative hypothesis,

µ > 25235

This is a right tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100,

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 27524

µ = population mean = 25235

s = samples standard deviation = 6000

t = (27524 - 25235)/(6000/√100) = 3.815

We would determine the p value using the t test calculator. It becomes

p = 0.000119

Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.

6 0
3 years ago
What is the solution to –4(8 – 3x) ≥ 6x – 8?
melisa1 [442]
-4(8-3x)≥6x-8
Expand the left side.
-32+12x≥6x-8
Add 32 to both sides
12x≥6x+24
Subtract 6x.
6x≥24
Divide both sides by 6.
x≥4

Answer: x ≥ 4
8 0
3 years ago
Find the greatest common factor of the following monomials: 20a3 and 8a2
dimulka [17.4K]

GCF of given monomials are 4a^2

<em><u>Solution:</u></em>

<em><u>Given that we have to find the greatest common factor</u></em>

Given monomials are:

20a^3 \text{ and } 8a^2

When we find all the factors of two or more numbers, and some factors are the same, then the largest of those common factors is the Greatest Common Factor

Let us first find the GCF of 20 and 8 and then find GCF of variables and then multiply them together

<em><u>GCF of 20 and 8:</u></em>

The factors of 8 are: 1, 2, 4, 8

The factors of 20 are: 1, 2, 4, 5, 10, 20

Then the greatest common factor is 4

GCF\ of\ a^3 \text{ and } a^2\\\\a^3 = a^2 \times a\\\\a^2 = a^2

Thus GCF is a^2

<em><u>Therefore GCF of monomials are:</u></em>

\text{GCF of } 20a^3 \text{ and } 8a^2 = 4 \times a^2 = 4a^2

Thus GCF of given monomials are 4a^2

5 0
3 years ago
If (3+y)/y=7, then y=<br> Please help :)
Makovka662 [10]
\frac{\big{3+y}}{\big{y}}=7\ \ \ \Rightarrow\ \ \  D:\ y \neq 0\\\\ \frac{\big{3+y}}{\big{y}}\cdot y=7\cdot y\\\\3+y=7y\\\\y-7y=-3\\\\-6y=-3\ /:(-6)\\\\y= \frac{3}{6} \\\\y= \frac{1}{2} \ \in\ D
3 0
4 years ago
Read 2 more answers
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