Answer:
4 different ways
Step-by-step explanation:
Total number of children = 4
Distribution of the 4 children :
Number of boys = 3 ; Number of girls = 1
Boy = B ; Girl = G
Possible combinations :
BBBG ; GBBB ; BBGB ; BGBB
From the pascal triangle number of e; number of outcomes = 2
Having exactly 3 boys and 1 girl
Hence, of any of the 4 four total children, 3 must be boys and 1 girl ;
Answer:
<h2>i) 3</h2><h2>ii) 5</h2>Step-by-step explanation:
Let H be the set of students who play Hokey
V be the set of students who play Volleyball
S be the set of students who play Soccer
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card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]
= 73 - [50 + (58-50) + (62-50)]
= 73 - [50 + 8 + 12]
= 73 - 70
= 3
………………………………………………
Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]
= 100 - 95
= 5
…………………
<u><em>Note</em></u> :
A Venn diagram might be helpful in such case.
