3 years ago

What is the area of triangle ABD? 7 cm 2 3.5 cm 2 6 cm 2 4.5 cm 2

Mathematics

1 answer:

Andrej [43]3 years ago

5 0

Answer:

4.5cm^2

Step-by-step explanation:

To find area of a triangle the formula is --> 1/2 base times height

so 3cm x 3cm = 9cm and divide by 2 --> 4.5 cm^2

You might be interested in

If a machine that prints designs on T-shirts prints 500 shirts in 3 hours, how many hours will it take to print designs on 1,800

LuckyWell [14K]

500 shirts / 3 hours = 166 2/3 shirts per hour.

Divide total shirts by shirts per hour:

1800 / 166 2/3 = 10.8 hours.

5 0

2 years ago

Read 2 more answers

Which table best represents the steps to solve the equation 8 + = 4?

aleksklad [387]

Usaully if you add a larger number with a smaller negative number you will get your answer is 8 + -4+4

5 0

3 years ago

The weight of an object on a particular scale is 142.2 lbs the measured weight may vary from the actual weight by at most 0.3 lb

algol13

Answer:

144.9 <= x <= 145.5

Step-by-step explanation:

145.2 + 3 = 145.5

145.2 - 3 = 144.9

144.9 <= x <= 145.5

3 0

2 years ago

5. The box plot summarizes the test scores for 100 students: u 55 60 65 70 75 80 85 90 95 100 Which term best describes the shap

ASHA 777 [7]

C would be the correct answer

7 0

2 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

$\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}$

Finally

$a=\frac{2S -2v_ot-2s_o}{t^2}$

5 0

3 years ago