Answer:
The values of p in the equation are 0 and 6
Step-by-step explanation:
First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p
2
−7p−4=(2p+1)(p−4)
So then the equation looks like:
\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}
2p+1
p
−
(2p+1)(p−4)
2p
2
+5
=−
p−4
5
To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:
\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}
(2p+1)(p−4)
p
2
−4p
−
(2p+1)(p−4)
2p
2
+5
=−
(p−4)(2p+1)
10p+5
Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.
(p^2-4p)-(2p^2+5)=-(10p+5)(p
2
−4p)−(2p
2
+5)=−(10p+5)
Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p
2
−4p)−(2p
2
+5) first:
(p^2-4p)-(2p^2+5)=-p^2-4p-5(p
2
−4p)−(2p
2
+5)=−p
2
−4p−5
-p^2-4p-5=-10p+5−p
2
−4p−5=−10p+5
Combine like terms:
-p^2-4p+0=-10p−p
2
−4p+0=−10p
-p^2+6p=0−p
2
+6p=0
Factor:
p=0, p=6p
It is 72 1/10. This is because 72 is a whole number and point one would be tenths.
Answer:
1) 
2) 
3) 
4) 40
5) 
Step-by-step explanation:
1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:
2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:
3) Apply the Distributive property and the Product property of exponents. Then, you obtain:
4) 
is a square of a sum, then, by definition you have:
Then:
The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40
5) Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:
$21.00
let the original price = 100%
then the discount price = 100 - 15 = 85%
divide $17.85 by 85 to obtain 1% then multiply by 100 to obtain original price.
original price = $17.85 × 
= $21
These equations do match up. All you have to do is find the solution to the first equation. After that, plug in that solution to the second equation. If it makes the equation true, then the equations match.
Hope this helps!
