The picture in the attached figure
we know that
volume of the regular pyramid=(1/3)*area of the base*height
area of the base=12*12-----> 144 units²
height=71 units
substitute
volume of the regular pyramid=(1/3)*144*71-----> 3408 units³
the answer is
3408 units³
we know that
volume of the regular pyramid=(1/3)*area of the base*height
area of the base=12*12-----> 144 units²
height=71 units
substitute
volume of the regular pyramid=(1/3)*144*71-----> 3408 units³
the answer is
3408 units³