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Delicious77 [7]
2 years ago
10

I need serious help...math is so confusing ​

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
3 0

Answer:

B

Step-by-step explanation:

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I need help with this I am giving 60 points
inna [77]

Answer:

<2 ≅<4 with reason of vertical angle theorem.

Step-by-step explanation:

The vertical angle theorem states that two opposite (non-adjacent) angles formed by 2 intersecting lines have equal measure. In this problem, we are given that the angles are vertical angles. So the statement is that <2 ≅<4 with reason of vertical angle theorem.

3 0
3 years ago
In the diagram, the radius of the outer circle is 5 centimeters and the area of the shaded region is 16π square centimeters. Fin
shusha [124]

Answer:

c because I did this one an yeah

8 0
2 years ago
How do you solve <br> 8|x+2|-6=5|x+2|+3
sergejj [24]

Answer:

x = 1 or x = -5

Step-by-step explanation:

Solve for x over the integers:

8 abs(x + 2) - 6 = 5 abs(x + 2) + 3

Subtract 5 abs(x + 2) - 6 from both sides:

3 abs(x + 2) = 9

Divide both sides by 3:

abs(x + 2) = 3

Split the equation into two possible cases:

x + 2 = 3 or x + 2 = -3

Subtract 2 from both sides:

x = 1 or x + 2 = -3

Subtract 2 from both sides:

Answer:  x = 1 or x = -5

7 0
3 years ago
Can someone please help me?
Tems11 [23]
You are right correct
3 0
2 years ago
Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and
ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

b)

P(X1+X2 = 1 | X2 = 0) =  np(1-p)ⁿ¹⁻¹

P(X1+X2 = 1| X2 = 1) = (1-p)ⁿ¹

P(X1 + X2 = 1) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

b)

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

If k = 0, then this probability is equal to P(X1 = 1) = np(1-p)ⁿ¹⁻¹

If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

P(X1+X2 = 1) = P(X1+X2 = 1| X2 = 1) * P(X2=1) + P(X1+X2 = 1| X2 = 0) * P(X2 = 0) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

4 0
3 years ago
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