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Try the distance formula
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Answer:
(n^3 + 4 n + 4487)/(n + 1)
Step-by-step explanation:
Simplify the following:
(n^3 + 4 n - 2 + 67^2)/(n + 1)
| | 6 | 7
× | | 6 | 7
| 4 | 6 | 9
4 | 0 | 2 | 0
4 | 4 | 8 | 9:
(n^3 + 4 n - 2 + 4489)/(n + 1)
Grouping like terms, n^3 + 4 n - 2 + 4489 = n^3 + 4 n + (4489 - 2):
(n^3 + 4 n + (4489 - 2))/(n + 1)
4489 - 2 = 4487:
Answer: (n^3 + 4 n + 4487)/(n + 1)
Answer:
12
Step-by-step explanation:
The first cave has 7 times more bats than the last cave. So if the 45th cave has b bats, then the first cave has 7b bats.
There are 77 bats in every row of 7 caves. So if there are 7b bats in the first cave, then there are 77−7b bats in caves 2 through 7.
Since there are also 77 bats in caves 2 through 8, that means cave #8 must have 7b bats. Repeating this logic:
#1 = 7b
#2-#7 = 77−7b
#8 = 7b
#9-#14 = 77−7b
#15 = 7b
#16-21 = 77−7b
#22 = 7b
#23-28 = 77−7b
#29 = 7b
So the first 29 caves have 5(7b) + 4(77−7b) = 308 + 7b bats.
Now we do the same thing from the other end. If cave #45 has b bats, then caves #39-#44 have 77−b bats. And since caves #38-44 have 77 bats, then cave #38 has b bats. Therefore:
#45 = b
#39-44 = 77−b
#38 = b
#32-37 = 77−b
#31 = b
So caves 31 through 45 have 3b + 2(77−b) = 154 + b bats.
Adding that to the first 29 caves, plus x number of bats in cave #30:
308 + 7b + x + 154 + b = 462 + 8b + x
We know this equals 490.
490 = 462 + 8b + x
28 = 8b + x
x is a maximum when b is a minimum, which is b = 2.
28 = 8(2) + x
x = 12
There are at most 12 bats in the 30th cave.
<u><em>Answer:</em></u>
24.2%
<u><em>Explanation:</em></u>
<u>The percentage of people choosing strawberry can be calculated as follows:</u>

<u>We have:</u>
Number of people choosing strawberry = 15 people
Total number of surveyed people = 17 + 10 + 17 + 3 + 15 = 62 people
<u>Substitute in the above rule to get the percentage as follows:</u>
%
Hope this helps :)
X = 2
<span>y = 3 </span>
<span>2 + 3 = 5 </span>
<span>2³ + 3² = 17 </span>
<span>------------------- </span>
<span>BUT: </span>
<span>x + y = 5 </span>
<span>x^y + y^ x = 17 </span>
<span>y = 5 - x</span>