A(-4, 2) and B(3, -2).
I will do number 2.
Let d(A, B) = distance between the two points.
d(A, B) = sqrt{(3 -(-4))^2 + (-2-2)^2}
d(A, B) = sqrt{(3 + 4))^2 + (-2-2)^2}
d(A, B) = sqrt{(7)^2 + (-4)^2}
d(A, B) = sqrt{49 + 16}
d(A, B) = sqrt{65}
Done!
Given:
4log1/2^w (2log1/2^u-3log1/2^v)
Req'd:
Single logarithm = ?
Sol'n:
First remove the parenthesis,
4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)
Simplify each term,
Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:
log 1/2 (w^4) + 2 log 1/2 (u) - 3 log 1/2 (v)
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)
We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):
Thus,
Log of 1/2 (w^4 u^2) - log of 1/2 (v^3)
then use the quotient property of logarithms which is log of b (x) - log of b (y) = log of b (x/y)
Therefore,
log of 1/2 (w^4 u^2 / v^3)
and for the final step and answer, reorder or rearrange w^4 and u^2:
log of 1/2 (u^2 w^4 / v^3)
Answer:
D)x = 2y ^ 2
Step-by-step explanation:
y = 2x ^ 2
To find the inverse exchange x and y
x = 2 y^2
Then solve for y
Divide by 2
x/2 = 2y^2 /2
x/2 = y^2
Take the square root of each side
±sqrt(x/2) = y
