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3 years ago

45(x-4)^2+9(x-4) factor completely

Mathematics

2 answers:

Mumz [18]3 years ago

7 0

Answer:

9(x-4) [5x-19]

Step-by-step explanation:

45(x-4)^2+9(x-4)

We can factor out a 9 (x-4)

9 (x-4) [5(x-4) +1)]

Distribute in side the parentheses

9(x-4) [5x-20+1]

9(x-4) [5x-19]

kondaur [170]3 years ago

5 0

Answer:

9(5x−19)(x−4)

Step-by-step explanation:

First you have to distribute

45x^2+−360x+720+(9)(x)+(9)(−4)

45x^2+−360x+720+9x+−36

Then you have to combine like terms

45x^2+−360x+720+9x+−36

(45x^2)+9-360+9x)+(720+-36)

45x^2−351x+684

9(5x−19)(x−4)

Hope this helped!

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