8. Kelly wants to buy a magazine that is $25. Later the magazine was marked up an additional 20%. What is the new price?

Which of the following equations does NOT represent a proportional relationship

jeka94

A proportional relationship has the form: y=mx
The first three options (y=(1/3)x, y=2x, and y=3.4x) have this form. The fourth option is:
y+1=2x
If we isolate y:
y+1-1=2x-1
y=2x-1, it does not have the form y=mx
Answer: The equation that does not represent a proportional relationship is: Fourth option: y+1=2x

6 0

3 years ago

10) Find the Greatest Common Factor between the two given numbers. 8.10

Bess [88]

Answer: GCF(8,10) = 2

Step-by-step explanation:

Factors of 8

1, 2, 4

Factors of 10

1, 2, 5

5 0

3 years ago

In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d

nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

Displacement A: 2.50 km and 45° north of west

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

Displacement B: 4.70 km and 60° south of east

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

Displacement C: 1.30 km and 25° south of west

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

Displacement D: 5.10 km due east (0°)

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

Displacement E: 1.70 km and 5° east of north

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

Displacement F: 7.20 km and 55° south of west

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

Note: minus (-) symbol to negative directions

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

$R = \sqrt{Rx^{2} +Ry^{2} }$

$R =\sqrt{(3.28)^{2}+(-6.57)^{2} }$

R = 7,34 km

To find the direction of the resultant:

tanФ = $\frac{Ry}{Rx}$

tanФ = $\frac{6.57}{3.28}$

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

Download pdf

3 0

3 years ago

The formula for finding the area of a square that has a side length, s, is A = s^2. If a square has an area of 40 square units,

Darina [25.2K]

A = s^2
A = 40

40 = s^2...by taking the square root of both sides, u eliminate the ^2
sqrt 40 = s
6.32 = s <===

4 0

3 years ago

Read 2 more answers

Simplify 1 · 0 - 0/y

nasty-shy [4]

The product of any number and 0 is zero. The expression is 1*0-0/y. 1*0 is obviously 0. 0/y is the same thing as 0 * 1/y, which is also zero. 0-0 is 0, so the answer is 0.

3 0

3 years ago