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ss7ja [257]
4 years ago
11

Determine which of the following expressions can be factored to (x+ 2)(x +2)

Mathematics
2 answers:
inna [77]3 years ago
6 0

(x+2)(x+2)

x^2+2x+2x+4

x^2+4x+4

Answer : C ( x^2+4x+4)

docker41 [41]3 years ago
6 0

Answer:

C. x2+4x+4

Step-by-step explanation:

If you multiply it out:

(x)(x) + 2x + 2x + 2(2)

x2 + 4x + 4

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8 0
3 years ago
What is the value of f(-8)
chubhunter [2.5K]

For this question, you didn't gave enough details.

Read the function given by the question first.

After that substitute x with - 8.

7 0
3 years ago
(5x^2-2x) + (10x^2-3x-1)
amid [387]

Answer:Graph for 5*​x^​2-​2*​x+​10*​x^​2-​3*​x-​1

6 0
3 years ago
marcus bought a booklet of tickets to use at the amusement park.he used 50% on the rides,1/3 of the tickets on video games, and
Ivahew [28]

No, i do not agree. To find this out, we will have to convert all of them into either decimals or percents. Let's convert these all into percents. A percent means 'out of 100', so if we add the percents all together, they should equal to 100. The rides is 50%. To convert 1/3 into a percent, divide the numerator by the denominator. You will get a decimal, so then multiply that by 100 or move the decimal two places to the right. So, 1 divided by 3 is equal to approximately 33%. Let's add 50 and 33 together. The total is 83%. So, like I said, a percent is out of 100. Subtract 83 out of 100 and you will get 17. So, the remaining percent has to be 17 percent, not 10%.

Hope it helps :)

8 0
3 years ago
The water height of a pool is determined by 8g2 + 3g - 4, the rate that the pool is filled, and 9g2 - 2g - 5, the rate that wate
Juliette [100K]

Part A

From the question, we know that

Rate at which pool is filled = 8g² + 3g - 4

Rate at which water leaves the pool = 9g² - 2g - 5

Hence, height of the pool would be = Rate at which pool is filled - Rate at which water leaves the pool

⇒ Height of the pool = 8g² + 3g - 4 - (9g² - 2g - 5)

⇒ Height of the pool = -g² + 5g + 1

Part B

Let water height be H

H (g) = -g² + 5g + 1

When g=1, H(1) = -(1)² + 5 (1) + 1 = 5 units

When g=2, H(2) = -(2)² + 5 (2) + 1 = -4+11 = 7 units

When g=3, H(3) = -(3)² + 5 (3) + 1 = -9+16 = 7 units

When g=4, H(4) = -(4)² + 5 (4) + 1 = -16+21 = 5 units

Part C

Now, we need to determine the value for g for which height would be maximum.

Looking at the expression that determines height, -g² + 5g + 1, we see that the coefficient of g² is negative. Hence the equation would represent a downward facing parabola, which means that the function H(g) will have a maxima point.

To find out the maxima point, differentiate H(g) with respect to g, and equate the resulting expression to zero.

\frac{d(H(g)}{dg} = -2g + 5 = 0

⇒ 2g = 5

⇒ g = 2.5

So at g = 2.5, the height of the water in the pool is maximum. [Note: nearest tenth means rounding till the first decimal point, hence the answer is g=2.5]

8 0
3 years ago
Read 2 more answers
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