Ask question

Ask question

All categories

2 years ago

14

The graph of quadratic functiong is shown on the grid. The coordinates of the x-intercepts, they-intercept, and the vertex are i

ntegers. What is the maximum value of g?

1 answer:

baherus [9]2 years ago

7 0

Answer:

The maximum value of the quadratic is 9, it's the very top point or the vertex.

You might be interested in

Find the value of the coefficient of

Korolek [52]

The solution to the problem is as follows:
<span>
the genaral term is 5Cr(-1)^r 2^r x^(5-2r)
and so need 5-2r = -1 => r = 3
Coeff is then 5C3 (-1)^3 2^3 = -80
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

7 0

3 years ago

What are the zeros of the polynomial function y=2x^3-7x^2+2x+3?

zlopas [31]

$y = 2 {x}^{3} - 7 {x}^{2} + 2x + 3$

By inspection 1 is a root of y ,
Hence , (x-1) is a factor of y ,

$\dfrac{2 {x}^{3} - 7 {x}^{2} + 2x + 3 }{x - 1} = 2 {x}^{2} - 5x - 3 \\ \\ 2 {x}^{2} - 5x - 3 = (2x + 1)(x - 3)$

Hence , the 2 other roots are -1/2 and 3 , and the above graphs confirms the same.

Hope it helps you :)

7 0

3 years ago

What is 4/9 over 21?

earnstyle [38]

Answer:

0.02116402116

Or otherwise written as- 0.211

3 0

3 years ago

Read 2 more answers

How many units<br> above the x-axis<br> is the point<br> located at (9, 6)?<br> pls help

svetlana [45]

Answer:

6 units above the x-axis

Step-by-step explanation:

The pair (9,6) are a set of coordinates that indicate how far away from the origin (0,0) the point is.

The coordinates are written (x,y) where 'x' is how far to the left or right of the y-axis (vertical) the point is. The 'y' is how far above or below the x-axis (horizontal) the point is.

So in this case, the set of (9,6) means that the point is located at 9 units to the right of the origin and the y-axis and 6 units above the x-axis

4 0

2 years ago

Read 2 more answers

Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r

likoan [24]

The value of q(x) is $2 x+5$

The value of r(x) is $6$

Explanation:

The given expression is $\frac{2 x^{2}+13 x+26}{x+4}$

We need to rewrite the expression in the form of $q(x)+\frac{r(x)}{b(x)}$

Simplifying the expression, we get,

$\frac{2 x^{2}+8 x+5x+26}{x+4}$

Separating the fractions, we have,

$\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}$

$2 x+\frac{5 x+26}{x+4}$ -----------(1)

Now, we shall further simplify the term $\frac{5 x+26}{x+4}$ , we get,

$\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}$

Common out 5 from the numerator, we have,

$\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$

Substituting the value $\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$ in the equation(1), we get,

$2 x+5+\frac{6}{x+1}$

Thus, the expression $\frac{2 x^{2}+13 x+26}{x+4}=2 x+5+\frac{6}{x+1}$ is in the form of $q(x)+\frac{r(x)}{b(x)}$

Hence, we have,

$q(x)=2 x+5$

$r(x)=6$ and

$b(x)=x+4$

5 0

3 years ago