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lord [1]
2 years ago
13

An engineer makes 135,500 a year. She must pay 22% in federal income taxes at the end of the year. How much income tax is she pa

ying per year?
Mathematics
2 answers:
Mamont248 [21]2 years ago
4 0

613636.363636

Hope this helps

quester [9]2 years ago
3 0

Answer:

klkkbkbj8r02385845394680906030636

Step-by-step explanation:

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5. A stove has a list price of $1,400. If the chain discount is 13/10/4, what's the net price? Also, what's
Arada [10]

Answer:

I think this is the answer. I tried.

Step-by-step explanation:

13/10/4 = .325

A. 1,400 x .325=455

Net Price=1,400-455 = 945

B. Trade Discount = 32.5%

6 0
3 years ago
The Pythagorean theorem is a^2+b^2=c^2<br> Solve for b.
rodikova [14]

Answer:

see explanation

Step-by-step explanation:

given

a² + b² = c² ( isolate b² by subtracting a² from both sides )

b² = c² - a² ( take the square root of both sides )

\sqrt{b^{2} } = ± \sqrt{c^2-a^2}

b = ± \sqrt{c^2-a^2}

3 0
2 years ago
Read 2 more answers
What is the value of x<br><br>46<br><br>56<br><br>67<br><br>134
AleksAgata [21]
Hey there!

1.) let's remember that a acute angel is very tiny, it is less then 90 degrees. So we would want to find one of your options that would be very small.

46 would seem to be the answer.

x=46

Hope this helps you.
8 0
3 years ago
Read 2 more answers
5x-7=2x+8 solve for x
Rzqust [24]

Answer:

x=5

Step-by-step explanation:

Simplifying 5x + -7 = 2x + 8 Reorder the terms: -7 + 5x = 2x + 8 Reorder the terms: -7 + 5x = 8 + 2x Solving -7 + 5x = 8 + 2x Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-2x' to each side of the equation. -7 + 5x + -2x = 8 + 2x + -2x Combine like terms: 5x + -2x = 3x -7 + 3x = 8 + 2x + -2x Combine like terms: 2x + -2x = 0 -7 + 3x = 8 + 0 -7 + 3x = 8 Add '7' to each side of the equation. -7 + 7 + 3x = 8 + 7 Combine like terms: -7 + 7 = 0 0 + 3x = 8 + 7 3x = 8 + 7 Combine like terms: 8 + 7 = 15 3x = 15 Divide each side by '3'. x = 5 Simplifying x = 5

3 0
2 years ago
Read 2 more answers
5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
3 years ago
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