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IrinaK [193]
3 years ago
8

Two pairs of consecutive sides are congruent

Mathematics
1 answer:
amm18123 years ago
7 0

Answer:

yes because if there the same they are

Step-by-step explanation:

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<h3>The option A) x^{10}z^7 is correct answer.</h3><h3>The correct simplification for the given expression \frac{x^{12}\times z^{11}}{x^2\times z^4} is x^{10}z^7</h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as \frac{x^{12}\times z^{11}}{x^2\times z^4}

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

\frac{x^{12}\times z^{11}}{x^2\times z^4}

=x^{12}\times z^{11}(x^{-2}\times z^{-4})   ( by using the identity \frac{1}{a^m}=a^{-m} )

=(x^{12}.x^{-2})\times (z^{11}.z^{-4})

=x^{12-2}\times z^{11-4} ( by using the identity a^m.a^n=a^{m+n} )

=x^{10}\times z^7

=x^{10}z^7

∴ \frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7

<h3>The correct simplification for the given expression \frac{x^{12}\times z^{11}}{x^2\times z^4} is x^{10}z^7</h3><h3>Hence option A) x^{10}z^7 is correct answer.</h3>

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Step-by-step explanation:

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