T_n = 3 * T_(n-1)
Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1
T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!
Short way (sometimes it works!)
T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648
3rd one 10 x 6 x 6
hope this is right
Answer:
The distributive property allows you multiply a sum in parenthesis by multiplying each addend separately, then add the products.
Step-by-step explanation:
How to use the distributive law example.
2(x+4) = 16
To use the distributive law in this example multiply 3 by all terms in the parenthesis. Multiply 2 and x, then 2 and 4 to open the parenthesis.
2x+8=16
That is how you use the distributive law.
To continue solving, subtract 8 from both sides.
2x+8-8=16-8
2x=8
Divide 2 from both sides.
2x/2=8/2
x=4
Hope this helps!
If not, I am sorry.
Answer:
This is such a unique language. What language is this? I wanna try and learn it
