NEED HELP!! Quadratic Equations and functions question.

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

4 0

Answer:

B and D are correct

Step-by-step explanation:

Hello,

to find the zeroes we need to solve y = 0

so D is correct

and we can write

$-5(x-4)^2+10=0\\5(x-4)^2=10\\ (x-4)^2=10/5=2\\ x-4=\sqrt{2} \ or \ x-4=-\sqrt{2}\\ x=4+\sqrt{2} \ \ or \ \ x=4-\sqrt{2}$

so B is correct

hope this helps

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can someone help me with this

stiks02 [169]

90000
Haha boogaloo booga

8 0

3 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

Troyanec [42]

Answer: 300

Step-by-step explanation:

Let the number be represented by x.

Therefore, based on the information given in the question, this can be expressed as:

36% of x = 108

36/100 × x = 108

0.36 × x = 108

0.36x = 108

x = 108/0.36

x = 300

Therefore, the number is 300

8 0

3 years ago

The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is soli

stiks02 [169]

The first line through points (-3, 0) and (-4, -1) is the orange line.

The second line, through (1, 1) and (2, -1) is the purple line.

Since they are both shaded below, the intersection of the shaded regions, is the region colored in blue.

Both lines are included, since they are solid lines.

The equation of the first line can be found as follows:

the slope is $\frac{0-(-1)}{-3-(-4)}=\frac{1}{1}=1$ , thus, the equation is:
$y-0=1(x-(-4))\\\\y=x+4$

The equation of the second line can be found as follows:

the slope is $\frac{1-(-1)}{1-2}= \frac{2}{-1}=-2$ ,

thus the equation of the second line is :

$y-1=-2(x-1)\\\\y-1=-2x+2\\\\y=-2x+3$

We have to decide on the direction of the inequality sign, so we pick a point, for example (0, 4) which is not in the colored regions of the lines,

so we write the inequalities so that they do not hold for (0, 4)

line 1:

y≥x+4

4≥0+4=4 is true, so we change the sign and write : y≤x+4

similarly, line 2:

y≤-2x+3

4≤-2*0+3=3, which is not true, so we have the correct direction.

Note that since the lines were solid, we include the equality case:

Answer:

the shaded region is the solution to the system of inequalities:

i) y≤x+4
ii) y≤-2x+3