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uysha [10]
3 years ago
6

Two bicyclists are 7/8 of the way through a mile long tunnel when a train approaches the closer end at 40 mph. The riders take o

ff at the same speed in opposite directions and each escapes the tunnel as the train passes them. How fast did they ride?
Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

the cyclists rode at 35 mph

Step-by-step explanation:

Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then

distance= speed*time

since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :

time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train

thus denoting v as the speed of the cyclists :

7/8*L / v = L / 40 mph

v = 7/8 * 40 mph = 35 mph

v= 35 mph

thus the cyclists rode at 35 mph

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Lynna [10]
For this case, the first thing we must do is define variables.
 We have then:
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 p: number of pies
 We now write the system of equations:
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 the baker makes no more than 40 tarts per day:
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Answer:

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Step-by-step explanation:

2 is supplementary to 1 so subtract 81 from 180 = 99.

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Answer:

240

Step-by-step explanation:

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geniusboy [140]

Answer:

White roses - 7

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Step-by-step explanation:

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