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IrinaK [193]
4 years ago
11

Find the limit: lim e−9x sin x x→0

Mathematics
1 answer:
11111nata11111 [884]4 years ago
6 0

Answer:

\displaystyle \lim_{x \to 0} e^\big{-9x} \sin x = 0

General Formulas and Concepts:

<u>Pre-Calculus</u>

  • Unit Circle

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \lim_{x \to 0} e^\big{-9x} \sin x

<u>Step 2: Evaluate</u>

  1. Limit Rule [Variable Direct Substitution]:                                                     \displaystyle \lim_{x \to 0} e^\big{-9x} \sin x = e^\big{-9(0)} \sin(0)
  2. Simplify:                                                                                                         \displaystyle \lim_{x \to 0} e^\big{-9x} \sin x = 0

Topic: AP Calculus AB/BC (Calculus I/I + II)  

Unit: Limits

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