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sergij07 [2.7K]

3 years ago

6

Graph the function f(x) = (x + 1)(x – 5). Use the drop-down menus to complete the steps needed to graph the function. Identify t

he x-intercepts: (–1, 0) and (5, 0) Find the midpoint between the intercepts: (2, 0) Find the vertex: Find the y-intercept: Plot another point, then draw the graph.

2 answers:

Sveta_85 [38]3 years ago

7 0

The Vertex is (2,-9)
and the y-intercept is (0,-5)

den301095 [7]3 years ago

3 0

Vertex = 2, -9
Intercept = 0, -5

You can find this by distributing the parenthesis and then finding the vertex using -b/2a.

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Sin(x2 y2 da r , where r is the region in the first quadrant between the circles with center the origin and radii 1 and 5

Rudik [331]

I assume there's a plus sign missing above...

Convert to polar coordinates, using

$\begin{cases}x(r,\theta)=r\cos\theta\\y(r,\theta)=r\sin\theta\end{cases}$

Then the Jacobian is

$\dfrac{\partial(x,y)}{\partial(r,\theta)}=\begin{vmatrix}x_r&y_r\\x_\theta&y_\theta\end{vmatrix}=\begin{vmatrix}\cos\theta&\sin\theta\\r\sin\theta&-r\cos\theta\end{vmatrix}=-r$

Then

$\mathrm dA=\mathrm dx\,\mathrm dy=|-r|\,\mathrm dr\,\mathrm d\theta=r\,\mathrm dr\,\mathrm d\theta$

so the integral can be written as

$\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_1^5r\sin(r^2)\,\mathrm dr\,\mathrm d\theta$

Let $s=r^2$ , so that $\dfrac{\mathrm ds}2=r\,\mathrm dr$ .

$\displaystyle\frac12\int_0^{\pi/2}\int_1^{25}\sin s\,\mathrm ds\,\mathrm d\theta=-\frac12(\cos25-\cos1)\int_0^{\pi/2}\mathrm d\theta=\frac\pi4(\cos1-\cos25)$

3 0

3 years ago

Pls help I’ll brainlest ASAP <br><br><br> Make this sentence better the building is old and ugly

Elden [556K]

Answer:

the building is aged and unique.

6 0

2 years ago

A newspaper poll asked respondents if they trusted "eco friendly" labels on cleaning products. Out of 1000 adults surveyed, 498

Paul [167]

Answer:

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=498 represent the adults that trust these labels

$\hat p=\frac{498}{1000}=0.498$ estimated proportion of respondents that trust these labels

$p_o=0.5$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of respondents that trust these labels is at least 50%:

Null hypothesis: $p\geq 0.5$

Alternative hypothesis: $p < 0.5$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.498 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=-0.126$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided but we can assume it as $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.

7 0

4 years ago

A police officer claims that the proportion of accidents that occur in the daytime (versus nighttime) at a certain intersection

Roman55 [17]

Answer: -1.78

Step-by-step explanation:

As per given description, we have

Population proportion : $p=0.35$

Sample size : n= 500

Sample proportion : $\hat{p}=\dfrac{156}{500}=0.312$

Test statistic for population proportion :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\=\dfrac{0.312-0.35}{\sqrt{\dfrac{0.35(1-0.35)}{500}}}\\\\=-1.78146747757\ \ \text{(Simplified)}\\\\\approx-1.78$

Hence, the test statistic for this hypothesis test for a proportion= -1.78

3 0

3 years ago

1)When adding two negative numbers, _________ the absolute value of the numbers and keep the negative sign.

butalik [34]

1) add.

for example -1 + -2 = - (||-1| + |-2||), which is -(1+2) or -3

2) subtract

for example 4 + -7 = -(||-7| + |4||), which is - |7 - 4| or -3

3) change
for example 3 - (- 2) = 3 + 2

4) -10

the sum is -10.25, which is closest to -10

4 0

3 years ago

Read 2 more answers