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2 years ago

Solve for x please show work

Mathematics

1 answer:

Vanyuwa [196]2 years ago

5 0

Answer:

it is 10 d a d a p a p a

Step-by-step explanation:

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Factorise :x^2y^2-16

Lyrx [107]

Answer:

(xy - 4)(xy + 4).

Step-by-step explanation:

The is the difference of 2 squares.

a^2 - b^2 = (a - b)(a + b: so we have:

x^2y^2 - 16 = (xy - 4)(xy + 4)

5 0

3 years ago

What is the equation of a line perpendicular to y=1/4x+2 that passes through the point (0,1)

ipn [44]

Answer: y = -4x + 1 or y = 1 - 4x

Step-by-step explanation:

First, we have to find the slope of the perpendicular. The slope of the line perpendicular to the other is the reciprocal and opposite value of the other line's slope.

This means that the slope perpendicular to y = 1/4x + 2 is -4, or -4/1.

Now we need to find the y-intercept, to do that we will use the equation y = mx + b. m = slope, b = y-intercept.

Plug in the values.

1 = -4(0) + b

Simplify.

1 = 0 + b

1 = b

Our y-intercept is 1.

Now we can form the slope-intercept equation for the line perpendicular to y = 1/4x + 2 that passes through the point (0, 1).

y = -4x + 1

8 0

2 years ago

What is the measure of MN? A. 45 B. 29 C. 74 D. 37

Diano4ka-milaya [45]

Answer:

45°

Step-by-step explanation:

There are sets of formulas you can refer to for different situations like this. In your case here, you need to apply the formula and solve for the unknown. My work is in the attachment.

7 0

3 years ago

Read 2 more answers

Integration: How would I get to this answer?

Scrat [10]

Given that $y$ attains a maximum at $x=1$ , it follows that $y'=0$ at that same point. So integrating once gives

$\displaystyle\int\frac{\mathrm d^2y}{\mathrm dx^2}\,\mathrm dx=\int-8x\,\mathrm dx$
$\dfrac{\mathrm dy}{\mathrm dx}=-4x^2+C_1$
$\implies -4(1)^2+C_1=0\implies C_1=4$

and so the first derivative is $y'=-4x^2+4$ .

Integrating again, you get

$\displaystyle\int\frac{\mathrm dy}{\mathrm dx}\,\mathrm dx=\int(-4x^2+4)\,\mathrm dx$
$y=-\dfrac43x^3+4x+C_2$

You know that this curve passes through the point (2, -1), which means when $x=2$ , you have $y=-1$ :

$-1=-\dfrac43(2)^3+4(2)+C_2$
$\implies C_2=\dfrac53$

and so

$y=-\dfrac43x^3+4x+\dfrac53$

7 0

3 years ago

) What is the solution to the system of equations?

yaroslaw [1]

$\begin{cases} y = -\cfrac{1}{3}x+2\\[1em] y = x + 2 \end{cases}\qquad \implies \stackrel{y}{-\cfrac{1}{3}x+2}~~=~~\stackrel{y}{\cfrac{}{}x + 2} \\\\\\ -\cfrac{1}{3}x=x\implies -x=3x\implies 0=4x\implies \cfrac{0}{4}=x\implies \boxed{0=x} \\\\\\ \stackrel{\textit{substituting on the 2nd equation}}{y = x + 2\implies y = 0+2\implies }\boxed{y = 2} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (0~~,~~2)~\hfill$

4 0

2 years ago