Question

Please help me someone

Answer 1

Answer:

D

Step-by-step explanation:

We can multiply the first fraction by the reciprocal of the second to get

$\frac{3x*(x-2)}{6x^2*(2x-4)}$

Taking out the 2 from the denominator, we get

$\frac{3x*(x-2)}{6x^2*2(x-2)}$

Canceling the (x-2) from the top and bottom gives us

$\frac{3x}{6x^2*2}$ or $\frac{3x}{12x^2}$

Now, dividing top and bottom by 3x gives us $\frac{1}{4x}$, or D