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zubka84 [21]
3 years ago
11

I don’t under this .

Mathematics
2 answers:
melomori [17]3 years ago
6 0

Answer:

The answer is QR,RS, and ST

Step-by-step explanation:

i hope this helps .

dybincka [34]3 years ago
6 0
Answer:QR,RS and ST
Explanation:
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Given the function f(x) = 4x - 2, explain and show how to find the average rate of change between x = 2 and x = 4.
zalisa [80]

Answer:

The average rate of change between x = 2 and x = 4 is of 4.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function f(x) in an interval [a,b] is given by:

A = \frac{f(b)-f(a)}{b-a}

In this question:

f(x) = 4x - 2, b = 4, a = 2

Thus:

f(b) = f(4) = 4(4) - 2 = 16 - 2 = 14

f(a) = f(2) = 4(2) - 2 = 8 - 2 = 6

Average rate of change:

A = \frac{f(b)-f(a)}{b-a}

A = \frac{14-6}{4-2}

A = \frac{8}{2}

A = 4

The average rate of change between x = 2 and x = 4 is of 4.

7 0
2 years ago
At noon, ship A is 50 km west of ship B. Ship A is sailing south at 10 km/h and ship B is sailing north at 20 km/h. How fast is
Lena [83]
So  hmmm check the picture below

so, we're looking for dr/dt then at 4:00pm or 4 hours later

now, keep in mind that, the distance "x", is not changing, is constant whilst "y" and "r" are moving, that simply means when taking the derivative, that goes to 0

\bf r^2=x^2+y^2\implies 2r\cfrac{dr}{dt}=0+2y\cfrac{dy}{dt}\implies \cfrac{dr}{dt}=\cfrac{y\frac{dy}{dt}}{r}\quad 
\begin{cases}
\cfrac{dy}{dt}=30\\
r=130\\
y=120
\end{cases}
\\\\\\
\cfrac{dr}{dt}=\cfrac{120\cdot 30}{130}

6 0
2 years ago
Aria invested $96,000 in an account paying an interest rate of 1.8% compounded
Maslowich

Answer:

9.2

Step-by-step explanation:

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What two formulas are necessary to find the area of a segment of a circle?
tresset_1 [31]

Answer:

They are: area of sector and area of triangle

Step-by-step explanation:

Area of segment=area of sector - area of triangle

So we need both the area of sector and area of triangle to calculate for the area of a segment

8 0
3 years ago
1. Recall the three modes of transportation in the 3D world: v1 = 1-u,-13 ,v,- 6 Is there anywhere in the 3D world that Gauss co
jolli1 [7]

Complete Question

The complete question is on the first uploaded image

Answer:

The answers and the explanation are on the second ,third and fourth uploaded image

Step-by-step explanation:

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