Question

X^2/16 + y^2/25 =1 The length of the major axis is: 5 10 25

Answer 1

Answer:

Major axis length = 10

Step-by-step explanation:

Given:

The equation given is:

$\frac{x^2}{16}+\frac{y^2}{25}=1$

The above equation represents a standard ellipse of the form:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$

If $a > b$ then 'a' is the semi-major axis length and 'b' is the semi-minor axis length.

If $a < b$, then 'a' is the semi-minor axis length and 'b' is the semi-major axis length.

On comparing the given equation with the standard form, we get:

$a^2=16\\a=\sqrt{16}=4\\\\b^2=25\\b=\sqrt{25}=5$

Here, b > a as 5 > 4. So, the length of major axis is twice the length of 'b' and is equal to:

Major axis length = $2\times b=2\times 5 =10$