1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hitman42 [59]
3 years ago
5

Rewrite using distributive property 21+30

Mathematics
1 answer:
Anarel [89]3 years ago
4 0

Answer:

(20 + 1) + (30)

Step-by-step explanation

i think that is the answer sorry if i'm wrong

You might be interested in
In the final round of a TV game show, contestants have a chance to increase their current winnings of $1 million to $2 million.
guapka [62]

Answer:

<h2>The contestant should not play.</h2>

Step-by-step explanation:

As per the given question, their current winning is $1 million.

The probability of the guessing to be true is 50% = \frac{50}{100} = \frac{1}{2}.

There is also a possibility of 50% to be wrong, which can reduced the winning amount to $500,000 that is the half of the current amount.

Hence, the contestant should not play.

8 0
3 years ago
Take the product 6and 7 from 50
34kurt
You would do 6 multiplied by 7 and then you would come up with 42. after you get 42 you will subtract it from 50.
3 0
2 years ago
Read 2 more answers
Bad gums may mean a bad heart. Researchers discovered that 79% of people who have suffered a heart attack had periodontal diseas
zysi [14]

Answer:

(A) 0.297

(B) 0.595

Step-by-step explanation:

Let,

H = a person who suffered from a heart attack

G = a person has the periodontal disease.

Given:

P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.15)+(0.33\times(1-0.15))\\=0.399

(A)

The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.15}{0.399} \\=0.29699\\\approx0.297

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.

(B)

Now if the probability of a person having a heart attack is, P (H) = 0.38.

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.38)+(0.33\times(1-0.38))\\=0.5048

Compute the probability of a person having a heart attack given that he or she has the disease:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.38}{0.5048}\\ =0.59469\\\approx0.595

The probability of a person having a heart attack given that he or she has the disease is 0.595.

4 0
3 years ago
Twelve new students are standing in a line. How many different ways can the first seven students in line order themselves
anzhelika [568]

Answer:

Step-by-step explanation:

hope this helps!

6 0
2 years ago
–21:(–2 – 5) + ( –14) + 6.(8 – 4.3)​
Paladinen [302]
Did you mean -21(-2-5)+(-14)+6(8-4.3) ?
If that, the answer is 155.2:)) im sorry if im wrong:((
4 0
2 years ago
Other questions:
  • Complete the missing reasons in the proof below
    10·1 answer
  • Help. divide and simplify(104i)/(3+i) express a in a + bi form
    13·1 answer
  • Please answer asap. Will mark brainliest!!!
    12·1 answer
  • How many gallons of 20% antifreeze should be mixed with 10 gallons of 92% antifreeze to obtain a 65% antifreeze mixture?
    6·1 answer
  • Please help me because I don't understand how to do it.:)
    13·1 answer
  • Divide.
    11·2 answers
  • A person invests 5000 dollars in a bank. The bank pays 6.5% interest compounded monthly. To the nearest tenth of a year, how lon
    6·2 answers
  • How do you do this question​
    9·2 answers
  • 1. What is common in the four
    9·1 answer
  • I’ll give brainliest
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!