3 years ago

Please help me please!!!!!!!!!!

Mathematics

1 answer:

Elodia [21]3 years ago

8 0

Answer:

shoot, sorry but I don't know

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I got 2 questions.

alexandr402 [8]

Answer:

1. In triangle ABC,

AC = a = 10, BC =b= 7 and ∠ C = 90°

By cosine law,

$AB^2 = 7^2 + 10^2 - 2\times 7\times 10 cos 90^{\circ}$

$AB^2 = 49 + 100 - 0$

$AB^2 = 149$

$AB= \sqrt{149}$

Now, by the law of sine,

$\frac{sin B}{10} = \frac{sin90^{\circ}}{\sqrt{149} }$

$sin B = \frac{10}{\sqrt{149} }$

$\angle B = 55.0079798014\approx 55.008^{\circ}$

2. In triangle ABC,

∠B = 30°, AB=c=10 and ∠C = 90°

∠A = 180°-(30+90)°=60°

$\frac{AC}{10}=sin30^{\circ}$

⇒ $AC = \frac{10}{2} = 5$

By Pythagoras,

$CB^2 = AB^2 - AC^2=10^2 - 5^2 = 100 - 25 = 75$

⇒ $CB = \sqrt{75} =8.66025403784\approx 8.66$

6 0

3 years ago

Read 2 more answers

The difference between a and b is 12. The number a is 5 more than 3 times the number b. Which of the following pairs of equation

klio [65]

Answer:

a+b=12

3b+5=a

Step-by-step explanation:

6 0

3 years ago

Subtract 2 16/21 - (-8 5/21). reduce if possible

amid [387]

Answer= 11. Two negatives equals a positive so you add them together.

3 0

3 years ago

Paul [167]

Answer: D. 3/2

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If triangle BNV ~ triangle BRG, BR=4x+7 and BG= 18 find the value of x

Bingel [31]

Answer:

x=5

Step-by-step explanation:

5 0

2 years ago

Please help me please!!!!!!!!!!​

Please help me please!!!!!!!!!!