What is the intersection of BE and plane ACH?
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Answer:
After solve the equations we get value of k=3
Step-by-step explanation:
We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.
If the lines are concurrent, they pass through same point.
Let:
First solving equation 1 and 2 to find values of x and y
From eq(1) we find value of x and put it in eq(2)
After solving we get value of y=-1
Now putting in eq(1) to get value of x
So, Value of x= 2
Now put value of x=2 and y=-1 into eq(3) to find value of k
So, After solve the equations we get value of k=3
The equation for the linear function whose graph contains the points (-1, -2) and (3, 10) is y = 3x + 1
<h3><u>Solution:</u></h3>Given that linear function whose graph contains the points (-1, -2) and (3, 10)
We have to find the equation of line
Any function of the form f (x) = m x + b, where m is not equal to 0 is called a linear function
So let us use the slope intercept form
<em><u>The slope intercept form is given as:</u></em>
y = mx + c
Where "m" is the slope of line and "c" is the y - intercept
Let us first find slope of line containing points (-1, -2) and (3, 10)
<em><u>The slope of line is given as:</u></em>
Thus the slope of line is "m" = 3
Substitute m = 3 and (x, y) = (-1, -2) in y = mx + c
-2 = 3(-1) + c
-2 = -3 + c
c = -2 + 3 = 1
Now substitute c = 1 and m = 3 in slope intercept form to get equation of line
y = 3x + 1
Thus the equation for the linear function is found out