PLEASE HELP The areas of two similar triangles are 50 dm2, and 32 dm2. The sum of their perimeters is 117 dm. What is the perime
ter of each of these triangles?
1 answer:
Answer:
65 dm and 52 dm
Step-by-step explanation:
If the scale factor of the sides is k, then the scale factor of the areas is k^2.
The scale factor of the areas is (32 dm^2)/(50 dm^2) = 0.64 = k^2
The scale factor of the sides is k = \sqrt(0.64) = 0.8
The perimeters are in a ratio of 1:0.8
x + 0.8x = 117
1.8x = 117
x = 65
0.8x = 0.8(65) = 52
The perimeters are 65 dm and 52 dm.
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