PLEASE HELP The areas of two similar triangles are 50 dm2, and 32 dm2. The sum of their perimeters is 117 dm. What is the perime
ter of each of these triangles?
1 answer:
Answer:
65 dm and 52 dm
Step-by-step explanation:
If the scale factor of the sides is k, then the scale factor of the areas is k^2.
The scale factor of the areas is (32 dm^2)/(50 dm^2) = 0.64 = k^2
The scale factor of the sides is k = \sqrt(0.64) = 0.8
The perimeters are in a ratio of 1:0.8
x + 0.8x = 117
1.8x = 117
x = 65
0.8x = 0.8(65) = 52
The perimeters are 65 dm and 52 dm.
You might be interested in
Answer:
D. 30%?
I'm not 100% sure but I think its D. Sorry if it's wrong.
Answer: True
Step-by-step explanation:
AB is congruent to RS
BC is congruent to ST
CD is congruent to TV
So DC would be congruent to VT
Answer:
c=57.8
Step-by-step explanation:
6*7+4=46
5*7=35
c= 46^2+35^2=57.80138
Answer:
0.5
Step-by-step explanation:
just divide in a calculator
Answer:
66
Step-by-step explanation:
