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Vera_Pavlovna [14]
3 years ago
12

Find the area of a circle with a radius of 7.

Mathematics
1 answer:
Mashutka [201]3 years ago
6 0

Step-by-step explanation:

area of circle= πr²

3.14×7×7

153.86 is the required area

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Does the numerator impact whether a fraction will have a finite or infinite decimal?
Misha Larkins [42]

Answer:DECIDING IF A FRACTION IS A FINITE OR INFINITE REPEATING DECIMAL ... Need a short break? RATIONAL and IRRATIONAL NUMBERS. The rational numbers are numbers that can be written in the form ab a b , ... start by putting the fraction in simplest form;; then, factor the denominator into primes.

Step-by-step explanation:

6 0
3 years ago
Do 5/7 and 30/42 form a proportion
GREYUIT [131]
5/7
6*5/6*7
30/42

30/42 = 30/42

Yes, 5/7 and 30/42 form a proportion.
4 0
3 years ago
4. The red graph (1) is the graph of f(x) = log(x). Describe the transformation of the blue function (2) and write the equation
sergey [27]

Answer:

Function f(x) is shifted 1 unit left and 1 unit up.

f(x)\rightarrow f(x+1)+1

Transformed function f(x+1)+1=\log(x+1)+1

Step-by-step explanation:

Given:

Red graph (Parent function):

f(x)=\log(x)

Blue graph (Transformed function)

From the graph we can see that the red graph is shifted 1 units left and 1 units up.

Translation Rules:

f(x)\rightarrow f(x+c)

If c>0 the function shifts c units to the left.

If c the function shifts c units to the right.

f(x)\rightarrow f(x)+c

If c>0 the function shifts c units to the up.

If c the function shifts c units to the down.

Applying the rules to f(x)

The transformation statement is thus given by:

f(x)\rightarrow f(x+1)+1

As function f(x) is shifted 1 unit left and 1 unit up.

Transformed function is given by:

f(x+1)+1=\log(x+1)+1

5 0
3 years ago
Evaluate the expression
lora16 [44]
The correct answer is B=4
5 0
3 years ago
Which ordered pair is a solution of the system of a linear equation below? Y= 1/4x +2 y= x-1
Tanya [424]

Answer:  x = 4, y = 3

<u>Step-by-step explanation:</u>

y=\dfrac{1}{4}x+2    and      y=x-1

Using substitution method we get:

x-1=\dfrac{1}{4}x+2\\\\\text{subtract}\ \dfrac{1}{4}x\ \text{from both sides}\rightarrow \dfrac{3}{4}x-1=2\\\\\text{add 1 to both sides}\rightarrow \dfrac{3}{4}x=3\\\\\text{multiply both sides by 4}\rightarrow 3x=12\\\\\text{divide both sides by 3}\rightarrow x=4\\\\\text{Insert x = 4 into one of the original equations to solve for y:}\\y=x-1\\y =(4)-1\\y=3

3 0
3 years ago
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