Answer:
The solution of the system of equations is the point
Step-by-step explanation:
we have
------> equation A
------> equation B
Using a graphing tool
we know that
The solution of the system of equations is the intersection point both graphs
The intersection point is
see the attached figure
therefore
The solution of the system of equations is the point
2-step equation scenario:
Bob wanted to purchase 2 hats and a pack of gum at one store; the pack of gum was $1.50, but the 2 hats did not have a price. Bob went to another store and found only 1 of the exact same hats that he found at the first store, and a the same pack of gum for a total of $30.
Question: what store has the better deal, where the total will be equal to the second store’s prices?
‘h’ = the hats
Here’s the equation:
2h+1.50=30.
Steps:
1.) Subtraction Property of Equality (inverse properties to combine like terms and define ‘h’): 2h=28.5. We subtracted +1.50 to cancel it out and move it to the other side of the = to combine like terms.
2.) Division Property of Equality (inverse property used to isolate ‘h’). 2h/2=28.5/2=14.25. We divided 2 from 2h to cancel it out and get h alone.
Therefore h=14.25.
This means that store 1 has the better deal, since 2(14.25)+1.50=30. So, Bob can have 2 hats and the pack of gum at store 1 for the same price as only 1 hat and a pack of gum at store 2.
Answer:
- see the attachment
- (x, y) = (1, 1)
Step-by-step explanation:
1. Since you have y > ..., the boundary line is dashed and the shading is above it (for y-values greater than the values on the line). The boundary line is ...
y = 2x+3
which has a y-intercept of 3 and a slope (rise/run) of 2. A graph is attached.
__
2. You can add the two equations to eliminate y:
(3x +y) +(x -y) = (4) +(0)
4x = 4
x = 1
1 - y = 0 . . . . substitute into the the second equation
1 = y . . . . . . . add y
The solution is (x, y) = (1, 1).
Answer:
C
Step-by-step explanation:
81x-64-49x-27
81x-49x-64-27
32x-91 (C)
The square root of 7 is 2.645....
and it lies between the numbers 2 and 3.