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IceJOKER [234]
3 years ago
12

An algebraic expression for 2 times a number plus 5

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0

Answer:

2x+5

Step-by-step explanation:

X represents the number in "2 times a number." You could insert any number into x.

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A package of cookies, packed , ate the fourth part at breakfast , then 3/5 at tea time. there are still 18 cookies in the pakage
Leno4ka [110]
Ok so
1/4 of total eaten
3/4 left
3/5 of 3/4 eaten
9/20 left
18=9/20 of whole
multiply both sides by 20
360=9 of whole
divide both sides by 9
40=whole


40 total originlly

5 0
3 years ago
Read 2 more answers
Solve for x <br><br> plssss helppp
zzz [600]

Answer:

I think it is 5.a

but i am not sure

Step-by-step explanation:

Hope it helps though :)

3 0
3 years ago
How would you Simplify this???????????
Korvikt [17]
Lets solve this problem:(5x^2)(5x^2)^2


so first of all you would do the () first


so lets do the first one first. 5x^2 = 5*5 wich would equal 25


so the () by each other means multiply


so now its: 25*(5x^2)^2

5x^2= 5*5=25 

now its: 25*25^2

do 25^2 first: 25 * 25 =625

625*25

625*25=15,625 

your answer 15,625


3 0
3 years ago
A) 12, 10, 7,3,<br> Rule:<br> b) 1,3,9, 27,<br> Rule:<br> I<br> c) 4, 19, 34, 49<br> Rule:
sergejj [24]
A the rule would be -1 times X
B the rule would be x3
C the rule would be +15
5 0
3 years ago
The probability distribution for the number of defects in a shipment of alarm clocks, based on past data, is given below. Find t
Kay [80]

Answer:

0.29

Step-by-step explanation:

Given :

n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4

P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01

The expected number of defect in a shipment can be obtained using the expected value formula :

Expected value, E(X) = Σx*p(x)

Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)

E(X) = 0.29

Hence, the expected number of defect in shipment is 0.29

3 0
3 years ago
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