Starting with <span>3x^2-7x+12=0, we divide all four terms by 3, resulting in the following factored form:
</span><span>
3(</span><span>x^2-[7/3]x+4)=0.
</span><span>
Since 3 cannot equal 0, we can focus on the following:
x^2 - 7/4 x =-4
This completes the assignment (describe Joe's steps up to this point).
If you wish to go further:
Next, take HALF of the coefficient of x and square your result:
(-7/[4][2])^2 = 49/64
Add this to both sides of </span>x^2 - 7/4 x =-4: <span>x^2 - 7/4x + 49/64 =-4+49/64
Rewrite the left side as (x-7/8)^2 and the right side as 49/64 - 256/64
Simplify the right side by combining these terms: -207/64
Then x-7/8 = plus or minus (1/8)sqrt(-207)
Next, x = 7/8 plus or minus (1/8)*i*</span>√207, or
7 plus or minus i*√207
x = ----------------------------------
8
Answer:
its a 90 degrees bc it's going clock wise
Answer:
Step-by-step explanation:
We are given that a and b are rational numbers where
and x is irrational number .
We have to prove a+bx is irrational number by contradiction.
Supposition:let a+bx is a rational number then it can be written in
form
where
where p and q are integers.
Proof:
After dividing p and q by common factor except 1 then we get

r and s are coprime therefore, there is no common factor of r and s except 1.
where r and s are integers.


When we subtract one rational from other rational number then we get again a rational number and we divide one rational by other rational number then we get quotient number which is also rational.
Therefore, the number on the right hand of equal to is rational number but x is a irrational number .A rational number is not equal to an irrational number .Therefore, it is contradict by taking a+bx is a rational number .Hence, a+bx is an irrational number.
Conclusion: a+bx is an irrational number.
13+5=18
The large bag would be 18 because you have to add 5 more ounces than 13