Answer:
B. The original purchase total must be at most to $44 before the discounts are applied.
Step-by-step explanation:
Solve the inequality by adding $10, then dividing by 0.8.
0.8x -$10 ≤ $25.20
0.8x ≤ $35.20 . . . . . . . . add $10
x ≤ $35.20/0.8 . . . . . . . divide by 0.8
x ≤ $44 . . . . . . . . . the before-discount purchase must be at most $44
Relations are ordered pair sets (x,y) mapping a value to another value
the set of 1st components is called the domain
the set of 2nd components is called the range
Answer:
90,30
Step-by-step explanation:
let the three times be 3x then,
3x-22=68
3x=68+22
3x=90
x=90/3
x=30
again,
3x=3*30=90
please support me and give me brainliest
Find 10% of $19,200 = 1,920
Find 2% of $1,920 = 384
12% = $2,304
19,200 - 2,304 = 16,896 (year 1)
Repeat this until you have your 5th year :)
Answer: There are 4 people who only go to the game on Saturday.
Step-by-step explanation:
Let the number of people go on Saturday be n(A).
Let the number of people go on Sunday be n(B).
Since we have given that
n(A) = 8
n(B) = 12
n(A∪B) = 16
According to rules, we get that
So, n(only go on Saturday) = n(only A) = n(A) - n(A∩B) = 8-4 = 4
Hence, there are 4 people who only go to the game on Saturday.
