1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shutvik [7]
3 years ago
5

High School Dropouts

Mathematics
1 answer:
White raven [17]3 years ago
7 0

Answer:

There are more females dropping than males each year and that there are more females than males

You might be interested in
Mr. McGee mowed 4/5 of his lawn. His three sons finished the mowing. Each son mowed the same amount. How much of the lawn did ea
liubo4ka [24]

Answer:

1 fifteenth, or 1/15

Step-by-step explanation:

If there are 3 sons multiply the fraction by 3 and then you have 12/15 because 12/15 is equal to 4/5, so the remaining is 3 out of 15, so divide that between the 3 sons and boom, 1/15th per son.  

5 0
3 years ago
A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a
Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

                                   p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

p^4 (1-p)

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

(1-p)^4p

Therefore the probability that you stop at the fifth flip would be

                                    p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

7 0
3 years ago
8 = 4 - 2x<br> - 2x +5 = 17<br> 12= - 3 ( x+ 5)
max2010maxim [7]
8 = 4 - 2x\\8 + 2x = 4\\2x = -4\\x = -2

- 2x +5 = 17\\-2x =12\\x = -6

12= - 3 ( x+ 5)\\12 = -3x -15\\-3x =27\\x= -9
5 0
3 years ago
23 times 536 what is the proodsuct to that number
Nikolay [14]
   
23 × 536 = 12328
==============



4 0
3 years ago
How many solutions does the following equation have? 10x-1=10x+4
zimovet [89]
  • Your answer is no solution.
  • Because if we transpose 10x to the left hand side with a change in the symbol, then it will become 0.
  • 10x - 1 = 10x +4
  • or, 10x - 10x = 4 + 5
  • or, 0 = 9
  • Hence, the equation has <em><u>no solution</u></em>.

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
2 years ago
Read 2 more answers
Other questions:
  • Help please show work
    10·1 answer
  • Write two possible solutions to the way inequality x&lt; 9-5
    7·1 answer
  • Question in photo (:
    13·1 answer
  • Kyle drew 4 polygons labeled A,B,C, and D. Figure A has twice as many sides as Figure B. Figure B has 3 vertices. Figure C has h
    12·1 answer
  • How do you reduce 2 1/32
    12·1 answer
  • Factorise<br>b^3−b^2+b−1,2b^3−b^2+b−2​
    9·1 answer
  • If s = -5 and t = 3, find the value of s 2t.<br><br> 75<br> 225<br> -75<br> 30
    5·2 answers
  • Heeeeeeeeeeeeeeeeeeeeeeeelpppppppppppp ​
    11·1 answer
  • Can someone help me with Question 1 Please? I forgot how to do it- Also, No links please!​
    8·2 answers
  • 16÷(2+12)2<br> What is the answer?<br><br> 2 14/25<br><br> 4 1/4<br><br> 6 2/5<br><br> 8 1/4
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!