Answer:
Step-by-step explanation:
Given a circle centre J
Let the radius of the circle =r
LK is tangent to circle J at point K
From the diagram attached
Theorem: The angle between a tangent and a radius is 90 degrees.
By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.
Using Pythagoras Theorem:
The length of the radius, 
there are no graphs but the equation is y=3x-1
Parallel lines have the same slope
Y = -8x + 8
The slope will be -8
Therefore: y = -8x + b
Plug in the point
7 = -8(9) + b
7 = -72 + b, b = 79
Solution: y = -8x + 79
Yo sup??
Lenght of two side will be equal to 20 in as its an isoceles triangle.
The third side will be
x^2=b^2+h^2 (by pythagoreas theorem)
=9^2+9^2
x=9√2 in
Therefore the perimeter is = 9+9+9√2
=9√2(√2+1) in
Hope this helps.
