Of course. I wish it will only go up !
<span>0.1428571428 would be the correct answer</span>
The depth of the water at the <em>deepest</em> point in the waterslide and to the nearest hundredth of a meter is approximately 0.19 meters. (Correct choice: A)
<h3>How to determine the depth of the water in a waterslide</h3>
In this question we should apply the concepts of <em>right</em> triangles and <em>trigonometric</em> functions to determine the height of the water within the waterslide. A geometric diagram of the <em>cross</em> section of the waterslide is presented below, which indicates the existence of <em>circular</em> symmetry.
Now we proceed to determine the height of the water:
cos α = (0.5 m/0.75 m)
α ≈ 48.190°
y = (0.75 m) · sin 48.190°
y = 0.559 m
x = 0.75 m - 0.559 m
x = 0.191 m
The depth of the water at the <em>deepest</em> point in the waterslide and to the nearest hundredth of a meter is approximately 0.19 meters. (Correct choice: A)
To learn more on trigonometry: brainly.com/question/22698523
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Answer:
the radius of the inflated balloon is:
Step-by-step explanation:
Since it is stated that the water balloon has a spherical shape: We can confidently use the formula for the volume of a sphere to calculate the radius.
Volume is denoted as 'V' and radius is denoted as 'r'.
Volume is 176,868 mm^3
Now we can solve for the radius r.
cube root both sides
the radius of the inflated balloon is:
Answer:
y=4, y =16, x=10, x=15
Step-by-step explanation:
Plug the x values in the x place and then solve from there and for y values plug em in and easy answer