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Elanso [62]
3 years ago
8

19 points

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0

Answer:

Those sympathetic to slavery in Union border states, such as Kentucky and Delaware, did not support the Emancipation Proclamation because it granted freedom to slaves if their home southern states did not join the Union by January 1, 1863.

Missouri, Maryland, Kentucky and Delaware were slave holding border states and not in rebellion from the Union so the Proclamation did not effect their slaves. But, the area of the border states were closely linked to the South and held political, economic, geographic, and social connections to the Southern (and Northern) states. This led border states to not support the Emancipation Proclamation.

Step-by-step explanation:

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If Lin runs 21 laps at the same rate (1.2 minutes per lap) how long does it take her?
Firlakuza [10]

Answer:

It takes her 25.2 mintes

Step-by-step explanation:

You can just multiply 21 by 1.2 because that's how long she takes per lap and you can get 25.2

8 0
3 years ago
Read 2 more answers
Solve irrational equation pls
rusak2 [61]
\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)



\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\

4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\

There's one more condition I forgot about
-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\

Finally
x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}
3 0
3 years ago
2x - 3y = 16
KIM [24]

Answer:A

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Laurie was scuba diving. Each time she dove 5 feet deeper, she would stop and clear her ears. After Laurie had checked her instr
stepladder [879]

Answer:

Laurie's maximum depth can be represented using the expressions :

(20 × 3) = 60

(3 × 4 × 5) = 60

Step-by-step explanation:

Each depth level at which ears are checked = 5 feets

Each Depth level at which instruments are checked = 20 feets

For Laurie to check her instrument ;

Number of times ears are checked = 20/5 = 4 times

This means that for Laurie to have checked her instrument 3 times :

(4 × 3 × 5) = 60 feets

Therefore, Laurie's maximum depth can be expressed as (4 × 3 × 5) = 60 feets

4 0
2 years ago
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I need help please ASAP
azamat

What is the question

7 0
3 years ago
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