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pogonyaev
4 years ago
9

How can I make the following equations in the form of y=mx+b? Y+3x=1 Y-6=2x

Mathematics
2 answers:
Elza [17]4 years ago
8 0
y+3x=1\\
y=-3x+1\\\\
y-6=2x\\
y=2x+6
vitfil [10]4 years ago
3 0
You have to make them both y equals.
y+3x=1
  -3x  -3x       Subtract 3x to both sides to get y on one side, alone.
y=-3x+1        Now its in y=mx+b form!
y=mx+b

y-6=2x
 +6  +6         Add 6 to both sides to get y alone
y=2x+6        Now its in y=mx+b form!
y=mx+b
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Answer:

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Step-by-step explanation:

From  the question we are told that  

      The  sample  mean difference is  \= x_m - \= x_f  =  0.07

       The  standard error  is  SE  =  0.03

Given that the confidence interval is  95% then the level of significance is mathematically evaluated as

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Next  we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is  Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as

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substituting values

         E =  1.96 *  0.03

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The 95% confidence interval  is mathematically represented as

      (\= x_m - \= x_f  ) - E  <  \mu_m - \mu_f

substituting values

     0.07 - 0.0588  <  \mu_m - \mu_f

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Step-by-step explanation:

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