Please help I need practice on this but I don't understand this concept, so please explain your answer. I really want to underst
2 answers:
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Answer:
a) There is a 6.69% probability that a randomly selected female student abstains from alcohol.
b) If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.
Step-by-step explanation:
This is a probability problem:
We have these following probabilities:
-20.7% of a woman attending an all-women college abstaining from alcohol.
-6% of a woman attending a coeducational college abstaining from alcohol.
-4.7% of a woman attending an all-women college
- 100%-4.7% = 95.3% of a woman attending a coeducational college.
(a) What is the probability that a randomly selected female student abstains from alcohol?
is the probability of a woman attending an all-women college being chosen and abstaining from alcohol. There is a 0.047 probability of a woman attending an all-women college being chosen and a 0.207 probability that she abstain from alcohol. So:
is the probability of a woman attending a coeducational college being chosen and abstaining from alcohol. There is a 0.953 probability of a woman attending a coeducational college being chosen and a 0.06 probability that she abstain from alcohol. So:
So, the probability of a randomly selected female student abstaining from alcohol is:
There is a 6.69% probability that a randomly selected female student abstains from alcohol.
(b) If a randomly selected female student abstains from alcohol, what is the probability she attends a coedücational colege?
<em>This can be formulated as the following problem:</em>
<em>What is the probability of B happening, knowing that A has happened.</em>
Here:
<em>What is the probability of a woman attending a coeducational college, knowing that she abstains from alcohol.</em>
It can be calculated by the following formula:
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
We have the following probabilities:
is the probability of a woman from a coeducational college being chosen. So
is the probability of a woman abstaining from alcohol, given that she attends a coeducational college. So
is the probability of a woman abstaining from alcohol. From a),
So, the probability that a randomly selected female student attends a coeducational college, given that she abstains from alcohol is:
If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.
Answer:
6.06 km
Step-by-step explanation:
The information given in the question can be represented by the three sides if a right angled triangle.
Let the direct line from the airplane to the start of the runway be represented by x. So that applying the appropriate trigonometric function, we have;
Cos θ =
Cos =
0.9903 =
⇒ x =
= 6.0588
x = 6.06 km
The direct line from the airplane to the stat of the runway is 6.06 km.