Answer:
There are multiple critical paths
Explanation:
The critical path method (CPM), or critical path analysis (CPA), is an algorithm for scheduling a set of project activities. It is commonly used in conjunction with the program evaluation and review technique (PERT). A critical path is determined by identifying the longest stretch of dependent activities and measuring the time required to complete them from start to finish.
The essential technique for using CPM is to construct a model of the project that includes the following:
- A list of all activities required to complete the project (typically categorized within a work breakdown structure),
- The time (duration) that each activity will take to complete,
- The dependencies between the activities and,
- Logical end points such as milestones or deliverable items.
Using these values, CPM calculates the longest path of planned activities to logical end points or to the end of the project, and the earliest and latest that each activity can start and finish without making the project longer. This process determines which activities are "critical" (i.e., on the longest path) and which have "total float" (i.e., can be delayed without making the project longer).
considering the above function of the cpm analysis because you have multiple path, there is tendency that more than path through the project network will have zero slack values.
Answer:
Code is in the attached screenshot.
Explanation:
Assumed it was written in Java based on your other question asked.
No, this website is not for study groups. It's more of a 'question and answer' website. There is no actual communication on one certain subject. Although I do know a few websites that have worked really well for me,where you can create and participate in study groups;
-studyblue
- studyhall
- getstudyroom
all of these are safe websites that are used by wide variety of students, therefore i'm sure you can find plenty of people interested in learning the same things as you!
Answer:
A) t = true
B) t = false
C) t = false
D) t = true
Explanation:
Part A, here 12 is greater than 1 so the condition is true.That is why "t" will hold "true".Part B, here 0 is not greater than 2 so this condition fails.Therefore "t" will hold "false" in this case.Part C,3*2=6 and we are comparing 5 with 6 Therefore condition fails here.That is why "t" will hold "false".Part D, here we are comparing 5 with 5 and both are equal.So "t" will hold "true".