In a volumetric analysis experiment, a solution of sodium oxalate (Na₂C₂O₄) in acidic solution in titrated with a solution of po
tassium permanganate (KMnO₄) according to the following balanced chemical equation
It required 40.0 mL of 0.0335 M KMnO₄ to reach the endpoint. What mass of Na₂C₂O₄ was present initially?
A. 0.179 g
B. 1.79 g
C. 0.0718 g
D. 11.2 g
E. 0.448 g
It required 40.0 mL of 0.0335 M KMnO₄ to reach the endpoint. What mass of Na₂C₂O₄ was present initially?
A. 0.179 g
B. 1.79 g
C. 0.0718 g
D. 11.2 g
E. 0.448 g
2 answers:
Answer:
0.448 g
Explanation:
The first step is to obtain the number of moles of KMnO4 reacted from the data given at end point. We now apply this result together with data from the balanced reaction equation in a simple proportion to obtain the amount of sodium oxalate that reacted. We then calculate the molar mass of the sodium oxalate and multiply this molar mass by number of moles of oxalate reacted in order to obtain the mass of oxalate reacted. See image attached for details.
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Answer:
There are 5.69*10²⁴ molecules in 9.45 moles.
Explanation:
The mole is defined as the amount of matter that particles have, that is, atoms and elementary entities.
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole and represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.
Then the following rule of three can be applied: if 1 mole contains 6.023 * 10²³ molecules, 9.45 moles, how many molecules will it have?
Solving:
amount of molecules= 5.69*10²⁴⁴ molecules
<u><em>There are 5.69*10²⁴ molecules in 9.45 moles.</em></u>
Answer: The standard enthalpy change is -607kJ
Explanation:
The given balanced chemical reaction is,
First we have to calculate the enthalpy of reaction .
where,
We are given:
Putting values in above equation, we get:
The standard enthalpy change is -607kJ