A. How many Joules of energy are required to raise 3.50kg of water from 38.5 to 75.0C ? (specific heat of water is 4.184J/g C)(1
2 answers:
A. How many Joules of energy are required to raise 3.50kg of water from 38.5 to 75.0C ? (specific heat of water is 4.184J/g C)(1000g=1kg)
Answer:
q = 534,506 Joules
q = 534.506 KiloJoules
534.506 KiloJoules or 534,506 Joules energy required to raise 3.50kg of water from 38.5 to 75.0C
<h3>What is sp.heat ?</h3>Sp. Heat is the heat required to increase the temperature of the 1 mass of a given substance by a C temperature.
The formula of specific heat Cp =
Where,
q = energy of substance (Joules / KiloJoules),
Cp = Specific heat capacity of the substance (J/Kg.C),
m = mass of the substance
∆T = Change in temp.
Explanation:
Given data from que: -
Mss of the water (m) = 3.50 Kg = 3.50 × 1000 gm = 3500 gm
specific heat capacity of water (Cp) = 4.184J/g C
Change in temp (∆T) = 75.0 - 38.5 = 36.5
now, put all above given data in formula
we get
Cp =
q = Cp ×m×∆T
q = 4.184×3500×36.5
q = 534,506 Joules
q = 534.506 KJ
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Answer:
The structures are shown below.
Explanation:
When the acid reacts with water, it loses one proton (H⁺) and forms a base, which is the conjugate base of its acid.
The formal charge of an atom can be calculated by:
FC = X - (Y + Z/2)
Where X is the valence electrons of the neutral atom, Y is the unshared electrons, and Z is the shared electrons in the molecule.
a) When HCl deprotonates, it forms Cl⁻ as the conjugate base. The neutral atom Cl has 7 valence electrons (X), the ion has 8 unshared electrons (Y) and none shared electrons, so FC = -1 The structure is shown below in figure a.
b) When Hbr deprotonates it forms Br- as the conjugate base. The neutral atom has 7 valence electrons (X), the ion has 8 unshared electrons (Y) and none shared electrons, so FC = -1. The structure is shown below in figure b.
c) When CH3COOH loses a proton, it forms the conjugate base CH3COO⁻. The carbon as 4 valence electrons, hydrogen has 1 valence electron and oxygen has 6 valence electrons. The first carbon make simple bonds with each hydrogen and with the second carbon, and so, all the electrons are shared, and it has FC = 4 - (0 + 8/2) = 0, as so the hydrogens have FC = 1 - (0 + 2/2) = 0.
The second carbon does 1 simple bond with the first carbon, a double bond with one oxygen, and a simple bond with the other oxygen, and so doesn't have unshared electrons, and FC = 4 - (0 + 8/2) = 0.
The first oxygen does a double bond with the carbon, and so it has 4 unshared electrons, so FC = 6 - (4 + 4/2) = 0. The second oxygen does a simple bond with the carbon, and so has 5 unshared electrons, so FC = 6 - (5 + 2/2) = 0.
The structure is shown in figure c.
Answer:
a) The theoretical yield is 408.45g of
b) Percent yield =
Explanation:
1. First determine the numer of moles of and
.
Molarity is expressed as:
M=
- For the
M=
Therefore there are 1.75 moles of
- For the
M=}{1Lsolution}[/tex]
Therefore there are 2.0 moles of
2. Write the balanced chemical equation for the synthesis of the barium white pigment, :
3. Determine the limiting reagent.
To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:
- For the :
- For the :
As the is the smalles quantity, this is the limiting reagent.
4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.
5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:
Percent yield =
Percent yield =
The real yield is the quantity of barium white pigment you obtained in the laboratory.