1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nutka1998 [239]
2 years ago
5

A. How many Joules of energy are required to raise 3.50kg of water from 38.5 to 75.0C ? (specific heat of water is 4.184J/g C)(1

000g=1kg)
b. How many grams of carbon are present if it requires 37.5 kJoules of energy to heat a sample from 30.0 to 55.0C ? (specific heat of carbon is 0.71 J/g C)

c. If 480.0 Joules is applies to a 50.0g sample of Hg in a thermometer that reads 25.0C, what will be the final temperature of the sample? (SH mercury is 0.14)

d. A 25.0kg sample of an unknown metal X requires 875kJ of energy to heat it from 55.0 to 125.0C. What is the specific heat of the unknown metal?


5.690x103 miles to meters.

900.0kg to grams

Please also give sig figs to all answers.

Answer fast please.
Chemistry
2 answers:
DochEvi [55]2 years ago
7 0

a.

A substance's specific heat tells you how much heat is required to increase the temperature of 1 g of that substance by 1°C.

The equation that establishes a relationshop between heat and change in temperature is

q = m • c • ∆T, where

q - heat absorbed

c - the specific heat of the substance, in your case of water

ΔT - the change in temperature, defined as the difference between the final temperature and the initial temperature

so:

q = 1.00 g • 4.18 J/g×°C • (75.0 - 38.5)°C

q = 152,57 J

just apply this formula for all exercises

Marta_Voda [28]2 years ago
5 0

A. How many Joules of energy are required to raise 3.50kg of water from 38.5 to 75.0C ? (specific heat of water is 4.184J/g C)(1000g=1kg)

Answer:

q = 534,506 Joules

q = 534.506 KiloJoules

534.506 KiloJoules or 534,506 Joules energy required to raise 3.50kg of water from 38.5 to 75.0C

<h3>What is sp.heat ?</h3>

Sp. Heat is the heat required to increase the temperature of the 1 mass of a given substance by a  1^{0} C temperature.

The formula of specific heat Cp = \frac{q}{m (∆T)}

Where,

q = energy of substance (Joules / KiloJoules),

Cp = Specific heat capacity of the substance (J/Kg.C),

m = mass of the substance

∆T = Change in temp.

Explanation:

Given data from que: -

Mss of the water (m) = 3.50 Kg = 3.50 × 1000 gm = 3500 gm

specific heat capacity of water (Cp) = 4.184J/g C

Change in temp (∆T) = 75.0 - 38.5 = 36.5

now, put all above given data in formula

we get

Cp = \frac{q}{m (∆T)}

q = Cp ×m×∆T

q = 4.184×3500×36.5

q = 534,506 Joules

q = 534.506 KJ

You might be interested in
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
1 year ago
What is the voltage of a circuit in a toaster with 12.0 amps of current and 8.0 ohms of resistance?
3241004551 [841]
The answer is 96 volts
3 0
3 years ago
Read 2 more answers
Which of the following compounds is least soluble in water?
hjlf

Answer:

3) iron (iii) hydroxide

Explanation:

4 0
2 years ago
Why is RNA chemically unstable?
Zepler [3.9K]
<span>When a large number of atoms of the same isotope are observed they will have a statistically consistent half life.
</span>An unstable nucleus contains a near excessive number of RNA chemical can spontaneously break apart into one or more nuclei all with a lighter  state. #believe
8 0
3 years ago
What is the expected ionic charge when group VI elements participate in ionic bonds?
valina [46]
Group 6 elements usually have extra electrons to make give them an octet. So, they have 6 electrons to start and when they have an octet, they have 8.

We can find the charge by doing simple math 6 - 8 = -2

Answer is D)
3 0
3 years ago
Other questions:
  • I will mark brainliest
    5·2 answers
  • If solar panels are placed under the sun at noon, then they will produce more energy than solar panels placed in the sun at dawn
    14·1 answer
  • A. draw the structure of the tetrahedral intermediate initially formed in the reaction shown. you do not have to consider stereo
    11·1 answer
  • Plants make their own food. The chemical reaction for this process is shown
    9·1 answer
  • The rate constant for a reaction is 4.65 L mol-1s-1. What is the overall order of the reaction? zero
    12·2 answers
  • Can someone please help me with these three questions, it will soon be due.
    8·1 answer
  • What name is given to group II elements in the periodic table
    6·2 answers
  • A teaspoon of dry coffee crystals dissolves when mixed in a cup of hot water. This process produces a coffee solution. Which ter
    7·2 answers
  • Using the image below, describe in at least 2 paragraphs, what is happening with the arrows. Name and explain the processes and
    14·1 answer
  • In your own words What is the average atomic mass of an element?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!