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ELEN [110]
3 years ago
14

Six multiplication problems involved in solving 325 x 89

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

(300*80) + (300*9) + (20*80) + (20*9) + (5*80) + (5*9) = 28925

Step-by-step explanation:

Given;

325 x 89

Expand 325 = 300 + 20 + 5

Expend 89.0 = 80 + 9

now multiple to two expanded numbers;

(300 + 20 + 5) x (80 + 9)

distribute the number accordingly as follows;

(300*80) + (300*9) + (20*80) + (20*9) + (5*80) + (5*9), now we have Six multiplication problems.

= 24,000 + 2700 + 1600 + 180 + 400 + 45

= 28925

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6 0
3 years ago
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There is a set of 12 cards numbered 1 to 12. A card is chosen at random. Event A is choosing a number less
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The number of permutations of picking 4 pens from the box is 30.

There are six different unique colored pens in a box.

We have to select four pens from the different unique colored pens.

We have to find in how many different orders the four pens can be selected.

<h3>What is a permutation?</h3>

A permutation is the number of different arrangements of a set of items in a particular definite order.

The formula used for permutation of n items for r selection is:

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Applying the permutation formula.

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Learn more about permutation here:

brainly.com/question/14767366

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1 year ago
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Answer:

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3 years ago
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