Answer:
<em>Her raise per hour is $3.</em>
Step-by-step explanation:
<u>Quadratic Equation</u>
The standard representation of a quadratic equation is:

where a,b, and c are constants.
It can be solved by using the quadratic formula:

Jill asks for an increase in the hourly wage she receives. Since she works in a Maths Center, the increase comes as a maths equation.
She must solve the equation:

The solution to the equation is the increase in her hourly wage.
Comparing with the general form, we have a=1, b=-6, c=9. Thus, the solutions are:



Since the square root is 0, there is only one solution:

x = 3
Thus, her raise per hour is $3.