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storchak [24]
3 years ago
14

Please help fassssst

Mathematics
1 answer:
Zarrin [17]3 years ago
8 0

Answer:

\dfrac{9}{2}

Step-by-step explanation:

You can do this using the quadratic equation:

x =\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

Let's first setup our expression:

4x² + 12x = 135

the quadratic formula is:

ax² + bx + c = 0

4x² + 12x - 135 = 0

Then:

a = 4

b = 12

c = -135

Now we plug in our coefficients and solve:

x =\dfrac{-12\pm\sqrt{12^{2}-4(4)(-135)}}{2(4)}

We solve for both to determine the positive one:

x =\dfrac{-12+ \sqrt{12^{2}-4(4)(-135)}}{2(4)}              x =\dfrac{-12- \sqrt{12^{2}-4(4)(-135)}}{2(4)}

x =\dfrac{-12+ \sqrt{144+2160}}{8}                        x =\dfrac{-12- \sqrt{144+2160}}{8}

x =\dfrac{-12+ \sqrt{2304}}{8}                                 x =\dfrac{-12- \sqrt{2304}}{8}

x =\dfrac{-12+ 48}{8}                                        x =\dfrac{-12- 48}{8}

x =\dfrac{36}{8} = \dfrac{9}{2}                                           x =\dfrac{-60}{8} = \dfrac{-15}{2}

So if you are looking for a positive solution, just take the positive one as x.

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Answer:

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