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nataly862011 [7]
3 years ago
8

What is the solution of the system?y=-8x-2 and y=-6x+4

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0
Hello : 
<span>y=-8x-2 and y=-6x+4
-8x-2 = -6x +4
-8x+6x =2+4
-2x =6
x = - 3
y = -6(-3)+4 =22</span>
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If f(x )= 2x - 3 find the value of f(3) + f(0)
Nana76 [90]

Answer:

0

Step-by-step explanation:

Let's find f(3) first

All we need to do is plug 3 in the place of x

2(3) - 3

6 - 3 = 3

Now let's find f(0)

Do the same thing for the first one, plug the new number in the place of x

2(0) - 3 = -3

Not add both answers up

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3 years ago
Solve. 12 – (2 × 3) A. 6 B. 12 C. 12(2) D. 23
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3 years ago
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Find the length of x.
Ivahew [28]
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3 years ago
Will mark brainliest
VMariaS [17]

Answer:

Interquartile range => 7

Third quartile => 22

Range => 13

First quartile => 15

Step-by-step explanation:

Order your data set, from the least amount to the highest amount:

$12, $14, $15, $15, $15, $15, $16, $22, $24, $25

Interquartile range (IQR) = third quartile (Q3) - first quartile (Q1)

Q1 = the middle value of the lower part of the data set, from the median to your left.

Q3 = the middle value of the upper part of the data set, from the median to your right.

The median lies between the 5th and 6th value that is enclosed in the parenthesis below:

$12, $14, ($15), $15, $15,[Median], $15, $16, ($22), $24, $25

The median divides the data set into upper and lower part.

Median = \frac{15 + 15}{2} = 15

First quartile: Q1 = $15

Third quartile: Q3 = $22

IQR = $22 - $15 = $7

Range = highest amount - least amount = 25 - 12 = $13

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3 years ago
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